Comments on: DRK 3 : TextField / DataValidation Example 1 http://www.mikechambers.com/blog/2003/04/23/drk-3-textfield-datavalidation-example-1/ code = joy Fri, 02 Dec 2011 01:36:37 +0000 hourly 1 http://wordpress.org/?v=3.1.3 By: Anonymous http://www.mikechambers.com/blog/2003/04/23/drk-3-textfield-datavalidation-example-1/comment-page-1/#comment-1480 Anonymous Thu, 22 May 2003 00:31:58 +0000 http://www.mikechambers.com/blog/?p=502#comment-1480 Geeze. It doesn't work if I enter "pi" either. Geeze. It doesn’t work if I enter “pi” either.

]]> By: Samuel Christie http://www.mikechambers.com/blog/2003/04/23/drk-3-textfield-datavalidation-example-1/comment-page-1/#comment-1479 Samuel Christie Thu, 15 May 2003 16:42:04 +0000 http://www.mikechambers.com/blog/?p=502#comment-1479 To be a little more technical, e is actually not the exponent of the preceeding number. It is, as you can see from my example, the exponent of 10. As in the following: 2e3 = 2*(10^3) = 2*1000 = 2000 Just thought I'd correct myself. To be a little more technical, e is actually not the exponent of the preceeding number. It is, as you can see from my example, the exponent of 10. As in the following:
2e3 = 2*(10^3) = 2*1000 = 2000

Just thought I’d correct myself.

]]> By: Samuel Christie http://www.mikechambers.com/blog/2003/04/23/drk-3-textfield-datavalidation-example-1/comment-page-1/#comment-1478 Samuel Christie Thu, 15 May 2003 16:39:13 +0000 http://www.mikechambers.com/blog/?p=502#comment-1478 e is the exponent not natural log: 2e3 = 2000 2e4 = 20000 etc. 2e is the same as 2e0 which should evaluate to 2 This is not a bug. The e is not a method, function, or constant. It is actually a part of the number itself. Think of the following analogy: "Can't" is a word though it stands for "Cannot" - should we rule it out because it's a contraction - no, of course not. 2e10 is a whole lot easier to write than 20000000000, and simply should not be excluded from this validation. e is the exponent not natural log:

2e3 = 2000
2e4 = 20000
etc.
2e is the same as 2e0 which should evaluate to 2
This is not a bug. The e is not a method, function, or constant. It is actually a part of the number itself. Think of the following analogy:
“Can’t” is a word though it stands for “Cannot” – should we rule it out because it’s a contraction – no, of course not. 2e10 is a whole lot easier to write than 20000000000, and simply should not be excluded from this validation.

]]> By: maxxxx http://www.mikechambers.com/blog/2003/04/23/drk-3-textfield-datavalidation-example-1/comment-page-1/#comment-1477 maxxxx Wed, 07 May 2003 18:55:16 +0000 http://www.mikechambers.com/blog/?p=502#comment-1477 maybe 2e stands for "2 elevated". anyway I think this should be invalid. maybe 2e stands for “2 elevated”. anyway I think this should be invalid.

]]> By: Phillip Kerman http://www.mikechambers.com/blog/2003/04/23/drk-3-textfield-datavalidation-example-1/comment-page-1/#comment-1476 Phillip Kerman Thu, 01 May 2003 06:20:55 +0000 http://www.mikechambers.com/blog/?p=502#comment-1476 Okay, I'll answer my own question. It appears to be a bug in Flash. Works fine in JavaScript (at least on IE Win). I don't know how I found that one. Phillip Okay, I’ll answer my own question. It appears to be a bug in Flash. Works fine in JavaScript (at least on IE Win).

I don’t know how I found that one.

Phillip

]]> By: Phillip Kerman http://www.mikechambers.com/blog/2003/04/23/drk-3-textfield-datavalidation-example-1/comment-page-1/#comment-1475 Phillip Kerman Wed, 30 Apr 2003 05:40:23 +0000 http://www.mikechambers.com/blog/?p=502#comment-1475 Try: 2e Did I break it or what? Or, do you count 'e' like the natural log...? Try:
2e

Did I break it or what?

Or, do you count ‘e’ like the natural log…?

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